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dominic
To new visitors the CME trading thread can be found in the FMA General Discussion Board
dominic
Let’s see who can solve this one:
IMG_0259.webp
B
Beesolberg
Let our integers be (n,n+2,n+4).

We then need the condition that 2n - 3(n+4) =15.
Solving:
2n-3n-12=15
-n=27
n=-27

We can verify by 2(-27)=-54 and 3(-23)=-69 so -54-(-69)=15. So our three integers are -27,-25,-23
  • Wow
Reactions: dominic
dominic
dominic
Outstanding…
Curious choice of n, n+2, and n+4

I used n+1,3,5 and got it wrong first try cause I tried to do too much in my head… and then I got -27, -25, -23 and it didn’t look right cause negative numbers and inequalities… anyway

Great stuff!!
dominic
Welcome all to the MCFAM forum, or MCForum, or the FMA forum or [insert alternate name]
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